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(A) primary alcohol is characterized by the functional group $-CH_2OH$ attached to a carbon chain.For the molecular formula $C_4H_{10}O$,we need to at

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$2$

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(A) primary alcohol is characterized by the functional group $-CH_2OH$ attached to a carbon chain.For the molecular formula $C_4H_{10}O$,we need to attach the $-CH_2OH$ group to a propyl radical $(C_3H_7)$.There are two possible isomers for the propyl radical:$1$. $n$-propyl group: $CH_3-CH_2-CH_2-$$2$. Isopropyl group: $(CH_3)_2CH-$Attaching the $-CH_2OH$ group to these radicals gives:$1$. $CH_3-CH_2-CH_2-CH_2OH$ ($n$-butanol)$2$. $(CH_3)_2CH-CH_2OH$ ($2$-methylpropan-$1$-ol)Thus,there are $2$ primary alcohols possible.

The number of primary alcohols possible with the formula $C_4H_{10}O$ is :-

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